Document page
mathematicsprinted 16 · PDF 17
165 pagesrevision 46935
printed 16 · PDF 17
Page image rendered from the stored file at 110 dpi; it sharpens as you zoom. Outlines are placed from each region’s stored position on the page (595 × 842 pt).
readable
Source of this text: embedded text layer. The better of the embedded text and OCR is kept.
16
Ratio of cow to sheep 2:3
Ratio of sheep to goat 6:7
We need to find a combined, 3-part ratio that shows the relative portions of all the
animals together
Notice that sheep appear in both ratios, so we can use sheep as the link between
the two
C:S = 2:3 and S:G = 6:7
We can multiply both sides of the C:S ratio by 2, so that both ratios are comparing
relative to 6 sheep
C:S = 4:6 and S:G = 6:7
These can now be joined together
C:S:G = 4:6:7
We can now use this to share the 85 animals in the ratio 4:6:7
There are 17 parts in total (4 + 6 + 7 = 17)
Each part is worth 5 animals (85 ÷ 17 = 5)
There are 20 cows (4 × 5), 30 sheep (6 × 5), and 35 goats(7 × 5)
Working with Proportion:
A way of talking about how two variables are related to each other